python3-pycurl: Upgrade 7.43.0.5 -> 7.43.0.6

Upgrade to release 7.43.0.6:

- Improve SSL backend detection on various systems
- Add support for libcurl's multiple SSL backend functionality
- Add support for several libcurl options

Signed-off-by: Leon Anavi <leon.anavi@konsulko.com>
Acked-by: Trevor Gamblin <trevor.gamblin@windriver.com>
Signed-off-by: Khem Raj <raj.khem@gmail.com>

meta-python/recipes-devtools/python/python3-pycurl_7.43.0.6.bb

@@ -0,0 +1,23 @@
+SUMMARY = "A Python Interface To The cURL library"
+DESCRIPTION = "\
+PycURL is a Python interface to libcurl, the multiprotocol file \
+transfer library. Similarly to the urllib Python module, PycURL can \
+be used to fetch objects identified by a URL from a Python program \
+"
+SECTION = "devel/python"
+HOMEPAGE = "http://pycurl.io/"
+
+LICENSE = "LGPLv2 | MIT"
+LIC_FILES_CHKSUM = "file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \
+                    file://COPYING-MIT;md5=60872a112595004233b769b6cbfd65b6 \
+                    "
+
+SRC_URI[md5sum] = "3e121d895101022c30619e1bbf97eb97"
+SRC_URI[sha256sum] = "8301518689daefa53726b59ded6b48f33751c383cf987b0ccfbbc4ed40281325"
+
+inherit pypi setuptools3
+
+DEPENDS = "\
+    curl \
+    ${PYTHON_PN}\
+"