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Replace "echo -e" with "printf" to have the same behavior in dash or bash
oe-core removed the prerequisite to have sh as bash. POSIX doesn't define any options and furthermore allows 'echo -e' to be the default behavior. This means that in dash 'echo -e' will actually print '-e' and interpret backslashes by default. We use instead 'printf' builtin command with or without '\n' to simulate 'echo -e' or 'echo -n'. 'printf' needs format while 'echo' can be used without any arguments. So 'echo >' was replaced by 'printf "" >'. 'echo' without '-n' flag adds a new line by default so to keep the same behavior of two new lines while using 'echo "\n"', 'printf "\n\n"' is used. [YOCTO #3138] (From OE-Core rev: a19880ad10ccb5d7d909dcf9de5c3dc58a0ebcd3) Signed-off-by: Andrei Gherzan <andrei@gherzan.ro> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
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Richard Purdie
parent
82a08d42ff
commit
42d91a7db4
@@ -181,7 +181,7 @@ ipk_log_check() {
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if (echo "$lf_txt" | grep -v log_check | grep "$keyword_die") >/dev/null 2>&1
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then
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echo "log_check: There were error messages in the logfile"
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echo -e "log_check: Matched keyword: [$keyword_die]\n"
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printf "log_check: Matched keyword: [$keyword_die]\n\n"
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echo "$lf_txt" | grep -v log_check | grep -C 5 -i "$keyword_die"
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echo ""
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do_exit=1
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