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base/license.bbclass: expand wildcards in INCOMPATIBLE_LICENSE

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The whitelist processing in code in base.bbclass does not play well with
wildcards in INCOMPATIBLE_LICENSES. The code expects bad_licenses to
contain actual license names, not wildcards.

Add incompatible_license_contains to replace bb.utils.contains(
"INCOMPATIBLE_LICENSE", **, **, **, d)

[YOCTO #5592]

(From OE-Core rev: 3587653a8d8abc7cfed6a5c6ecfa72bee283e451)

Signed-off-by: Hongxu Jia <hongxu.jia@windriver.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
This commit is contained in:
Hongxu Jia
2014-12-15 16:55:10 +08:00
committed by Richard Purdie
parent fc518325c6
commit 5f78cf9b4e
3 changed files with 27 additions and 2 deletions
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meta/classes/license.bbclass
+25
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@@ -285,6 +285,31 @@ def canonical_license(d, license):
lic += '+'
return lic or license
def expand_wildcard_licenses(d, wildcard_licenses):
"""
Return actual spdx format license names if wildcard used. We expand
wildcards from SPDXLICENSEMAP flags and SRC_DISTRIBUTE_LICENSES values.
"""
import fnmatch
licenses = []
spdxmapkeys = d.getVarFlags('SPDXLICENSEMAP').keys()
for wld_lic in wildcard_licenses:
spdxflags = fnmatch.filter(spdxmapkeys, wld_lic)
licenses += [d.getVarFlag('SPDXLICENSEMAP', flag) for flag in spdxflags]
spdx_lics = (d.getVar('SRC_DISTRIBUTE_LICENSES') or '').split()
for wld_lic in wildcard_licenses:
licenses += fnmatch.filter(spdx_lics, wld_lic)
licenses = list(set(licenses))
return licenses
def incompatible_license_contains(license, truevalue, falsevalue, d):
license = canonical_license(d, license)
bad_licenses = (d.getVar('INCOMPATIBLE_LICENSE', True) or "").split()
bad_licenses = expand_wildcard_licenses(d, bad_licenses)
return truevalue if license in bad_licenses else falsevalue
def incompatible_license(d, dont_want_licenses, package=None):
"""
This function checks if a recipe has only incompatible licenses. It also